95120414211333 has 8 divisors (see below), whose sum is σ = 144945393083968. Its totient is φ = 54354522406464.

The previous prime is 95120414211301. The next prime is 95120414211371. The reversal of 95120414211333 is 33311241402159.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 95120414211333 - 2⁵ = 95120414211301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 95120414211291 and 95120414211300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (95120414211133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2264771766916 + ... + 2264771766957.

It is an arithmetic number, because the mean of its divisors is an integer number (18118174135496).

Almost surely, 2^{95120414211333} is an apocalyptic number.

It is an amenable number.

95120414211333 is a deficient number, since it is larger than the sum of its proper divisors (49824978872635).

95120414211333 is a wasteful number, since it uses less digits than its factorization.

95120414211333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4529543533883.

The product of its (nonzero) digits is 77760, while the sum is 39.

The spelling of 95120414211333 in words is "ninety-five trillion, one hundred twenty billion, four hundred fourteen million, two hundred eleven thousand, three hundred thirty-three".