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95120414211301 is a prime number
BaseRepresentation
bin10101101000001011110010…
…011111111111110011100101
3110110210102102012210010110021
4111220023302133333303211
544431423102014230201
6534145414240355141
726015136352243453
oct2550136237776345
9413712365703407
1095120414211301
1128343383046926
12a802b82315ab1
13410ca80014cab
14196bbd17d59d3
15aee4785c2ea1
hex5682f27ffce5

95120414211301 has 2 divisors, whose sum is σ = 95120414211302. Its totient is φ = 95120414211300.

The previous prime is 95120414211269. The next prime is 95120414211371. The reversal of 95120414211301 is 10311241402159.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85408926473025 + 9711487738276 = 9241695^2 + 3116326^2 .

It is a cyclic number.

It is not a de Polignac number, because 95120414211301 - 25 = 95120414211269 is a prime.

It is a super-2 number, since 2×951204142113012 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (95120414211371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47560207105650 + 47560207105651.

It is an arithmetic number, because the mean of its divisors is an integer number (47560207105651).

Almost surely, 295120414211301 is an apocalyptic number.

It is an amenable number.

95120414211301 is a deficient number, since it is larger than the sum of its proper divisors (1).

95120414211301 is an equidigital number, since it uses as much as digits as its factorization.

95120414211301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 34.

The spelling of 95120414211301 in words is "ninety-five trillion, one hundred twenty billion, four hundred fourteen million, two hundred eleven thousand, three hundred one".