Base | Representation |
---|---|
bin | 10101101000100110010110… |
… | …101010000101000001010011 |
3 | 110110220011001002112220000022 |
4 | 111220212112222011001103 |
5 | 44432410011124340144 |
6 | 534210452503014055 |
7 | 26020166246420066 |
oct | 2550462652050123 |
9 | 413804032486008 |
10 | 95148938121299 |
11 | 28354490050667 |
12 | a808602a3a32b |
13 | 4112677639b4a |
14 | 196d339ba28dd |
15 | b00097826cee |
hex | 568996a85053 |
95148938121299 has 2 divisors, whose sum is σ = 95148938121300. Its totient is φ = 95148938121298.
The previous prime is 95148938121271. The next prime is 95148938121311. The reversal of 95148938121299 is 99212183984159.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 95148938121299 - 28 = 95148938121043 is a prime.
It is a super-2 number, since 2×951489381212992 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (95148938121229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47574469060649 + 47574469060650.
It is an arithmetic number, because the mean of its divisors is an integer number (47574469060650).
Almost surely, 295148938121299 is an apocalyptic number.
95148938121299 is a deficient number, since it is larger than the sum of its proper divisors (1).
95148938121299 is an equidigital number, since it uses as much as digits as its factorization.
95148938121299 is an evil number, because the sum of its binary digits is even.
The product of its digits is 100776960, while the sum is 71.
The spelling of 95148938121299 in words is "ninety-five trillion, one hundred forty-eight billion, nine hundred thirty-eight million, one hundred twenty-one thousand, two hundred ninety-nine".
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