Base | Representation |
---|---|
bin | 10101101010001001110001… |
… | …011111000011000110001011 |
3 | 110111021100120201111212221201 |
4 | 111222021301133003012023 |
5 | 44441132122243431433 |
6 | 534331505333245031 |
7 | 26030665523115424 |
oct | 2552116137030613 |
9 | 414240521455851 |
10 | 95255688655243 |
11 | 2839578aa31836 |
12 | a825235493777 |
13 | 411c75a868b6c |
14 | 19745855a264b |
15 | b02c444eea7d |
hex | 56a2717c318b |
95255688655243 has 2 divisors, whose sum is σ = 95255688655244. Its totient is φ = 95255688655242.
The previous prime is 95255688655229. The next prime is 95255688655271. The reversal of 95255688655243 is 34255688655259.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 95255688655243 - 221 = 95255686558091 is a prime.
It is a super-2 number, since 2×952556886552432 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (95255688605243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47627844327621 + 47627844327622.
It is an arithmetic number, because the mean of its divisors is an integer number (47627844327622).
Almost surely, 295255688655243 is an apocalyptic number.
95255688655243 is a deficient number, since it is larger than the sum of its proper divisors (1).
95255688655243 is an equidigital number, since it uses as much as digits as its factorization.
95255688655243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3110400000, while the sum is 73.
The spelling of 95255688655243 in words is "ninety-five trillion, two hundred fifty-five billion, six hundred eighty-eight million, six hundred fifty-five thousand, two hundred forty-three".
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