Base | Representation |
---|---|
bin | 10101101011011000101101… |
… | …101010111101000001011001 |
3 | 110111120110100220110010020201 |
4 | 111223120231222331001121 |
5 | 44444024220232140241 |
6 | 534434444225022201 |
7 | 26040056144012563 |
oct | 2553305552750131 |
9 | 414513326403221 |
10 | 95340450271321 |
11 | 28418726726512 |
12 | a83974ba84961 |
13 | 4127748326188 |
14 | 19787068a8333 |
15 | b05055a37931 |
hex | 56b62dabd059 |
95340450271321 has 2 divisors, whose sum is σ = 95340450271322. Its totient is φ = 95340450271320.
The previous prime is 95340450271303. The next prime is 95340450271331. The reversal of 95340450271321 is 12317205404359.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 85240995086025 + 10099455185296 = 9232605^2 + 3177964^2 .
It is a cyclic number.
It is not a de Polignac number, because 95340450271321 - 235 = 95306090532953 is a prime.
It is not a weakly prime, because it can be changed into another prime (95340450271331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47670225135660 + 47670225135661.
It is an arithmetic number, because the mean of its divisors is an integer number (47670225135661).
Almost surely, 295340450271321 is an apocalyptic number.
It is an amenable number.
95340450271321 is a deficient number, since it is larger than the sum of its proper divisors (1).
95340450271321 is an equidigital number, since it uses as much as digits as its factorization.
95340450271321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 907200, while the sum is 46.
The spelling of 95340450271321 in words is "ninety-five trillion, three hundred forty billion, four hundred fifty million, two hundred seventy-one thousand, three hundred twenty-one".
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