9540134041 has 2 divisors, whose sum is σ = 9540134042. Its totient is φ = 9540134040.

The previous prime is 9540134027. The next prime is 9540134059. The reversal of 9540134041 is 1404310459.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9506250000 + 33884041 = 97500^2 + 5821^2 .

It is an emirp because it is prime and its reverse (1404310459) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9540134041 - 2¹³ = 9540125849 is a prime.

It is a super-3 number, since 3×9540134041³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 9540133994 and 9540134012.

It is not a weakly prime, because it can be changed into another prime (9540144041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4770067020 + 4770067021.

It is an arithmetic number, because the mean of its divisors is an integer number (4770067021).

Almost surely, 2^9540134041 is an apocalyptic number.

It is an amenable number.

9540134041 is a deficient number, since it is larger than the sum of its proper divisors (1).

9540134041 is an equidigital number, since it uses as much as digits as its factorization.

9540134041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

The square root of 9540134041 is about 97673.6097469526. The cubic root of 9540134041 is about 2120.8900707353.

The spelling of 9540134041 in words is "nine billion, five hundred forty million, one hundred thirty-four thousand, forty-one".