95414113 has 2 divisors, whose sum is σ = 95414114. Its totient is φ = 95414112.

The previous prime is 95414107. The next prime is 95414117. The reversal of 95414113 is 31141459.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95413824 + 289 = 9768^2 + 17^2 .

It is an emirp because it is prime and its reverse (31141459) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-95414113 is a prime.

It is not a weakly prime, because it can be changed into another prime (95414117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47707056 + 47707057.

It is an arithmetic number, because the mean of its divisors is an integer number (47707057).

Almost surely, 2^95414113 is an apocalyptic number.

It is an amenable number.

95414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

95414113 is an equidigital number, since it uses as much as digits as its factorization.

95414113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2160, while the sum is 28.

The square root of 95414113 is about 9768.0147931911. The cubic root of 95414113 is about 456.9523050647.

The spelling of 95414113 in words is "ninety-five million, four hundred fourteen thousand, one hundred thirteen".