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95455540553 is a prime number
BaseRepresentation
bin101100011100110010…
…1111111010101001001
3100010101110102212211212
41120321211333111021
53030443104244203
6111503543302505
76616322464412
oct1307145772511
9303343385755
1095455540553
113753418949a
12165bba4aa35
13900316a699
1448976a0809
15273a2b81d8
hex163997f549

95455540553 has 2 divisors, whose sum is σ = 95455540554. Its totient is φ = 95455540552.

The previous prime is 95455540471. The next prime is 95455540559. The reversal of 95455540553 is 35504555459.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82307019664 + 13148520889 = 286892^2 + 114667^2 .

It is an emirp because it is prime and its reverse (35504555459) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 95455540553 - 236 = 26736063817 is a prime.

It is a super-2 number, since 2×954555405532 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (95455540559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47727770276 + 47727770277.

It is an arithmetic number, because the mean of its divisors is an integer number (47727770277).

Almost surely, 295455540553 is an apocalyptic number.

It is an amenable number.

95455540553 is a deficient number, since it is larger than the sum of its proper divisors (1).

95455540553 is an equidigital number, since it uses as much as digits as its factorization.

95455540553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6750000, while the sum is 50.

The spelling of 95455540553 in words is "ninety-five billion, four hundred fifty-five million, five hundred forty thousand, five hundred fifty-three".