Base | Representation |
---|---|
bin | 10101101111111110101001… |
… | …000100011101011110000001 |
3 | 110112200121222210222102110001 |
4 | 111233332221010131132001 |
5 | 100014212044102334001 |
6 | 535235441214240001 |
7 | 26101631112250024 |
oct | 2557765104353601 |
9 | 415617883872401 |
10 | 95656053168001 |
11 | 2852a5602a0a47 |
12 | a88a94a7b6001 |
13 | 414b433872011 |
14 | 1989ac5d2d1bb |
15 | b0d377dec001 |
hex | 56ffa911d781 |
95656053168001 has 2 divisors, whose sum is σ = 95656053168002. Its totient is φ = 95656053168000.
The previous prime is 95656053167933. The next prime is 95656053168019. The reversal of 95656053168001 is 10086135065659.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53473314377025 + 42182738790976 = 7312545^2 + 6494824^2 .
It is a cyclic number.
It is not a de Polignac number, because 95656053168001 - 213 = 95656053159809 is a prime.
It is not a weakly prime, because it can be changed into another prime (95656053160001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47828026584000 + 47828026584001.
It is an arithmetic number, because the mean of its divisors is an integer number (47828026584001).
Almost surely, 295656053168001 is an apocalyptic number.
It is an amenable number.
95656053168001 is a deficient number, since it is larger than the sum of its proper divisors (1).
95656053168001 is an equidigital number, since it uses as much as digits as its factorization.
95656053168001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832000, while the sum is 55.
The spelling of 95656053168001 in words is "ninety-five trillion, six hundred fifty-six billion, fifty-three million, one hundred sixty-eight thousand, one".
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