960100000053 has 4 divisors (see below), whose sum is σ = 1280133333408. Its totient is φ = 640066666700.

The previous prime is 960100000051. The next prime is 960100000121. The reversal of 960100000053 is 350000001069.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 960100000053 - 2¹ = 960100000051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 960099999969 and 960100000032.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (960100000051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160016666673 + ... + 160016666678.

It is an arithmetic number, because the mean of its divisors is an integer number (320033333352).

Almost surely, 2^960100000053 is an apocalyptic number.

It is an amenable number.

960100000053 is a deficient number, since it is larger than the sum of its proper divisors (320033333355).

960100000053 is a wasteful number, since it uses less digits than its factorization.

960100000053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 320033333354.

The product of its (nonzero) digits is 810, while the sum is 24.

The spelling of 960100000053 in words is "nine hundred sixty billion, one hundred million, fifty-three", and thus it is an aban number.