96047538314112 has 1280 divisors, whose sum is σ = 369318390312960. Its totient is φ = 24047124480000.

The previous prime is 96047538314093. The next prime is 96047538314129. The reversal of 96047538314112 is 21141383574069.

96047538314112 is a `hidden beast` number, since 9 + 60 + 4 + 7 + 538 + 3 + 1 + 41 + 1 + 2 = 666.

It is a super-2 number, since 2×96047538314112² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (54).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 6360335362 + ... + 6360350462.

It is an arithmetic number, because the mean of its divisors is an integer number (288529992432).

It is a 1-persistent number, because it is pandigital, but 2⋅96047538314112 = 192095076628224 is not.

Almost surely, 2^{96047538314112} is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 96047538314112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (184659195156480).

96047538314112 is an abundant number, since it is smaller than the sum of its proper divisors (273270851998848).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

96047538314112 is a wasteful number, since it uses less digits than its factorization.

96047538314112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15433 (or 15412 counting only the distinct ones).

The product of its (nonzero) digits is 4354560, while the sum is 54.

The spelling of 96047538314112 in words is "ninety-six trillion, forty-seven billion, five hundred thirty-eight million, three hundred fourteen thousand, one hundred twelve".