Base | Representation |
---|---|
bin | 10101111010011010000101… |
… | …011101100100101111011001 |
3 | 110122020010211020020100002211 |
4 | 111322122011131210233121 |
5 | 100112432310104410131 |
6 | 540545003023155121 |
7 | 26204461504041112 |
oct | 2572320535445731 |
9 | 418203736210084 |
10 | 96372715310041 |
11 | 287864913a7565 |
12 | a985817445aa1 |
13 | 41a0ba600a9b1 |
14 | 19b26700c7209 |
15 | b21d1eb905b1 |
hex | 57a685764bd9 |
96372715310041 has 2 divisors, whose sum is σ = 96372715310042. Its totient is φ = 96372715310040.
The previous prime is 96372715309939. The next prime is 96372715310089. The reversal of 96372715310041 is 14001351727369.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 80010520419600 + 16362194890441 = 8944860^2 + 4045021^2 .
It is a cyclic number.
It is not a de Polignac number, because 96372715310041 - 29 = 96372715309529 is a prime.
It is not a weakly prime, because it can be changed into another prime (96372715310941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48186357655020 + 48186357655021.
It is an arithmetic number, because the mean of its divisors is an integer number (48186357655021).
Almost surely, 296372715310041 is an apocalyptic number.
It is an amenable number.
96372715310041 is a deficient number, since it is larger than the sum of its proper divisors (1).
96372715310041 is an equidigital number, since it uses as much as digits as its factorization.
96372715310041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 952560, while the sum is 49.
The spelling of 96372715310041 in words is "ninety-six trillion, three hundred seventy-two billion, seven hundred fifteen million, three hundred ten thousand, forty-one".
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