Search a number
-
+
96375243508993 is a prime number
BaseRepresentation
bin10101111010011100011100…
…001001111000110100000001
3110122020101100102111011002001
4111322130130021320310001
5100113002444314241433
6540550101535224001
726204611243264411
oct2572343411706401
9418211312434061
1096375243508993
1128787569510889
12a986202078001
1341a11b9a313c7
1419b282db98641
15b21e1badb57d
hex57a71c278d01

96375243508993 has 2 divisors, whose sum is σ = 96375243508994. Its totient is φ = 96375243508992.

The previous prime is 96375243508979. The next prime is 96375243509009. The reversal of 96375243508993 is 39980534257369.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71434478379664 + 24940765129329 = 8451892^2 + 4994073^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-96375243508993 is a prime.

It is a super-2 number, since 2×963752435089932 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (96375243508963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48187621754496 + 48187621754497.

It is an arithmetic number, because the mean of its divisors is an integer number (48187621754497).

Almost surely, 296375243508993 is an apocalyptic number.

It is an amenable number.

96375243508993 is a deficient number, since it is larger than the sum of its proper divisors (1).

96375243508993 is an equidigital number, since it uses as much as digits as its factorization.

96375243508993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1322697600, while the sum is 73.

The spelling of 96375243508993 in words is "ninety-six trillion, three hundred seventy-five billion, two hundred forty-three million, five hundred eight thousand, nine hundred ninety-three".