Base | Representation |
---|---|
bin | 10101111101100100100001… |
… | …010011011101111110101011 |
3 | 110122222220212121222211220021 |
4 | 111331210201103131332223 |
5 | 100130012440014141103 |
6 | 541232511441541311 |
7 | 26226255116525533 |
oct | 2575444123357653 |
9 | 418886777884807 |
10 | 96590078271403 |
11 | 2885a6930a4602 |
12 | a9bb979944837 |
13 | 41b8536593bb2 |
14 | 19bcdb016a4c3 |
15 | b277e25d5bbd |
hex | 57d9214ddfab |
96590078271403 has 2 divisors, whose sum is σ = 96590078271404. Its totient is φ = 96590078271402.
The previous prime is 96590078271389. The next prime is 96590078271409. The reversal of 96590078271403 is 30417287009569.
It is a strong prime.
It is an emirp because it is prime and its reverse (30417287009569) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 96590078271403 - 233 = 96581488336811 is a prime.
It is not a weakly prime, because it can be changed into another prime (96590078271409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48295039135701 + 48295039135702.
It is an arithmetic number, because the mean of its divisors is an integer number (48295039135702).
It is a 1-persistent number, because it is pandigital, but 2⋅96590078271403 = 193180156542806 is not.
Almost surely, 296590078271403 is an apocalyptic number.
96590078271403 is a deficient number, since it is larger than the sum of its proper divisors (1).
96590078271403 is an equidigital number, since it uses as much as digits as its factorization.
96590078271403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22861440, while the sum is 61.
The spelling of 96590078271403 in words is "ninety-six trillion, five hundred ninety billion, seventy-eight million, two hundred seventy-one thousand, four hundred three".
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