Base | Representation |
---|---|
bin | 11100001101101110110… |
… | …01101101100000100011 |
3 | 10102200022021001220011212 |
4 | 32012313121231200203 |
5 | 111340410310042011 |
6 | 2021205014300335 |
7 | 130016512145402 |
oct | 16066731554043 |
9 | 3380267056155 |
10 | 969444612131 |
11 | 344159234826 |
12 | 137a750576ab |
13 | 70558b27a88 |
14 | 34cc8349639 |
15 | 1a33ded308b |
hex | e1b766d823 |
969444612131 has 2 divisors, whose sum is σ = 969444612132. Its totient is φ = 969444612130.
The previous prime is 969444612041. The next prime is 969444612137. The reversal of 969444612131 is 131216444969.
It is a strong prime.
It is an emirp because it is prime and its reverse (131216444969) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 969444612131 - 218 = 969444349987 is a prime.
It is a super-3 number, since 3×9694446121313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 969444612131.
It is not a weakly prime, because it can be changed into another prime (969444612137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 484722306065 + 484722306066.
It is an arithmetic number, because the mean of its divisors is an integer number (484722306066).
Almost surely, 2969444612131 is an apocalyptic number.
969444612131 is a deficient number, since it is larger than the sum of its proper divisors (1).
969444612131 is an equidigital number, since it uses as much as digits as its factorization.
969444612131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1119744, while the sum is 50.
The spelling of 969444612131 in words is "nine hundred sixty-nine billion, four hundred forty-four million, six hundred twelve thousand, one hundred thirty-one".
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