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96947874903 = 3112937814391
BaseRepresentation
bin101101001001010001…
…0110010110001010111
3100021020110112022201110
41122102202302301113
53042022123444103
6112312013230103
710001313224415
oct1322242626127
9307213468643
1096947874903
113812a603370
1216957792333
1391b03a7769
14499996a2b5
1527c62eb403
hex16928b2c57

96947874903 has 8 divisors (see below), whose sum is σ = 141015090816. Its totient is φ = 58756287800.

The previous prime is 96947874887. The next prime is 96947874923. The reversal of 96947874903 is 30947874969.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 96947874903 - 24 = 96947874887 is a prime.

It is an alternating number because its digits alternate between odd and even.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (96947874923) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1468907163 + ... + 1468907228.

It is an arithmetic number, because the mean of its divisors is an integer number (17626886352).

Almost surely, 296947874903 is an apocalyptic number.

96947874903 is a deficient number, since it is larger than the sum of its proper divisors (44067215913).

96947874903 is a wasteful number, since it uses less digits than its factorization.

96947874903 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2937814405.

The product of its (nonzero) digits is 82301184, while the sum is 66.

Adding to 96947874903 its sum of digits (66), we get a palindrome (96947874969).

The spelling of 96947874903 in words is "ninety-six billion, nine hundred forty-seven million, eight hundred seventy-four thousand, nine hundred three".

Divisors: 1 3 11 33 2937814391 8813443173 32315958301 96947874903