Base | Representation |
---|---|
bin | 111001110100011… |
… | …010100001011001 |
3 | 2111121022012200111 |
4 | 321310122201121 |
5 | 3441312311213 |
6 | 240131204321 |
7 | 33016134064 |
oct | 7164324131 |
9 | 2447265614 |
10 | 970041433 |
11 | 458621539 |
12 | 230a466a1 |
13 | 125c7b01a |
14 | 92b8d8db |
15 | 5a264a3d |
hex | 39d1a859 |
970041433 has 2 divisors, whose sum is σ = 970041434. Its totient is φ = 970041432.
The previous prime is 970041407. The next prime is 970041439. The reversal of 970041433 is 334140079.
970041433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 822370329 + 147671104 = 28677^2 + 12152^2 .
It is a cyclic number.
It is not a de Polignac number, because 970041433 - 225 = 936487001 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 970041395 and 970041404.
It is not a weakly prime, because it can be changed into another prime (970041439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 485020716 + 485020717.
It is an arithmetic number, because the mean of its divisors is an integer number (485020717).
Almost surely, 2970041433 is an apocalyptic number.
It is an amenable number.
970041433 is a deficient number, since it is larger than the sum of its proper divisors (1).
970041433 is an equidigital number, since it uses as much as digits as its factorization.
970041433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 31.
The square root of 970041433 is about 31145.4881644196. The cubic root of 970041433 is about 989.9123933633.
The spelling of 970041433 in words is "nine hundred seventy million, forty-one thousand, four hundred thirty-three".
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