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97042232184913 is a prime number
BaseRepresentation
bin10110000100001001100111…
…110001110001000001010001
3110201121010222000100112101101
4112010021213301301001101
5100204414442414404123
6542220330325304401
726304032656423531
oct2604114761610121
9421533860315341
1097042232184913
1128a1441a201064
12aa73527265101
13421c073c88592
1419d6c24b414c1
15b344579daaad
hex584267c71051

97042232184913 has 2 divisors, whose sum is σ = 97042232184914. Its totient is φ = 97042232184912.

The previous prime is 97042232184899. The next prime is 97042232184917. The reversal of 97042232184913 is 31948123224079.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90954998443089 + 6087233741824 = 9537033^2 + 2467232^2 .

It is a cyclic number.

It is not a de Polignac number, because 97042232184913 - 217 = 97042232053841 is a prime.

It is not a weakly prime, because it can be changed into another prime (97042232184917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48521116092456 + 48521116092457.

It is an arithmetic number, because the mean of its divisors is an integer number (48521116092457).

Almost surely, 297042232184913 is an apocalyptic number.

It is an amenable number.

97042232184913 is a deficient number, since it is larger than the sum of its proper divisors (1).

97042232184913 is an equidigital number, since it uses as much as digits as its factorization.

97042232184913 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5225472, while the sum is 55.

The spelling of 97042232184913 in words is "ninety-seven trillion, forty-two billion, two hundred thirty-two million, one hundred eighty-four thousand, nine hundred thirteen".