Base | Representation |
---|---|
bin | 11100010001001101001… |
… | …10000011110100001011 |
3 | 10102212010021100112011102 |
4 | 32020212212003310023 |
5 | 111403220342321303 |
6 | 2022114054452015 |
7 | 130113653540423 |
oct | 16104646036413 |
9 | 3385107315142 |
10 | 971310120203 |
11 | 344a26271635 |
12 | 1382b596400b |
13 | 70795472bc7 |
14 | 35023dd5483 |
15 | 1a3ecb7b288 |
hex | e226983d0b |
971310120203 has 2 divisors, whose sum is σ = 971310120204. Its totient is φ = 971310120202.
The previous prime is 971310120169. The next prime is 971310120251. The reversal of 971310120203 is 302021013179.
It is a weak prime.
It is an emirp because it is prime and its reverse (302021013179) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 971310120203 - 28 = 971310119947 is a prime.
It is a super-2 number, since 2×9713101202032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (971310120283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 485655060101 + 485655060102.
It is an arithmetic number, because the mean of its divisors is an integer number (485655060102).
Almost surely, 2971310120203 is an apocalyptic number.
971310120203 is a deficient number, since it is larger than the sum of its proper divisors (1).
971310120203 is an equidigital number, since it uses as much as digits as its factorization.
971310120203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 29.
The spelling of 971310120203 in words is "nine hundred seventy-one billion, three hundred ten million, one hundred twenty thousand, two hundred three".
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