Base | Representation |
---|---|
bin | 10110010001111100010011… |
… | …110011011011111001011001 |
3 | 110211221202100100121102210222 |
4 | 112101330103303123321121 |
5 | 100320432020320441303 |
6 | 544223553433045425 |
7 | 26432354552360645 |
oct | 2621742363337131 |
9 | 424852310542728 |
10 | 97990011108953 |
11 | 2924a36a749737 |
12 | aba7154556875 |
13 | 428a5592b3972 |
14 | 1a2aa55891c25 |
15 | b4de298ca938 |
hex | 591f13cdbe59 |
97990011108953 has 2 divisors, whose sum is σ = 97990011108954. Its totient is φ = 97990011108952.
The previous prime is 97990011108937. The next prime is 97990011109043. The reversal of 97990011108953 is 35980111009979.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 90341451155344 + 7648559953609 = 9504812^2 + 2765603^2 .
It is a cyclic number.
It is not a de Polignac number, because 97990011108953 - 24 = 97990011108937 is a prime.
It is not a weakly prime, because it can be changed into another prime (97990011108853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48995005554476 + 48995005554477.
It is an arithmetic number, because the mean of its divisors is an integer number (48995005554477).
Almost surely, 297990011108953 is an apocalyptic number.
It is an amenable number.
97990011108953 is a deficient number, since it is larger than the sum of its proper divisors (1).
97990011108953 is an equidigital number, since it uses as much as digits as its factorization.
97990011108953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5511240, while the sum is 62.
The spelling of 97990011108953 in words is "ninety-seven trillion, nine hundred ninety billion, eleven million, one hundred eight thousand, nine hundred fifty-three".
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