Base | Representation |
---|---|
bin | 11100100100001010001… |
… | …01000000010100110011 |
3 | 10110211101101121102021112 |
4 | 32102011011000110303 |
5 | 112040040204202032 |
6 | 2030515454343535 |
7 | 130624055522651 |
oct | 16220505002463 |
9 | 3424341542245 |
10 | 981485225267 |
11 | 349277905678 |
12 | 13a2754babab |
13 | 7172750c231 |
14 | 3570b4d9dd1 |
15 | 1a7e60c71b2 |
hex | e485140533 |
981485225267 has 2 divisors, whose sum is σ = 981485225268. Its totient is φ = 981485225266.
The previous prime is 981485225209. The next prime is 981485225293. The reversal of 981485225267 is 762522584189.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 981485225267 - 222 = 981481030963 is a prime.
It is not a weakly prime, because it can be changed into another prime (981485225767) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 490742612633 + 490742612634.
It is an arithmetic number, because the mean of its divisors is an integer number (490742612634).
Almost surely, 2981485225267 is an apocalyptic number.
981485225267 is a deficient number, since it is larger than the sum of its proper divisors (1).
981485225267 is an equidigital number, since it uses as much as digits as its factorization.
981485225267 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 19353600, while the sum is 59.
The spelling of 981485225267 in words is "nine hundred eighty-one billion, four hundred eighty-five million, two hundred twenty-five thousand, two hundred sixty-seven".
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