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98422342895473 is a prime number
BaseRepresentation
bin10110011000001110111100…
…110010010100011101110001
3110220111002021022010201221121
4112120032330302110131301
5100400022424240123343
6545154333343422241
726505531260051152
oct2630167462243561
9426432238121847
1098422342895473
11293a6754776863
12b056aab5b4981
1342bc25810b41c
141a43949a43929
15b5a2ce99caed
hex5983bcc94771

98422342895473 has 2 divisors, whose sum is σ = 98422342895474. Its totient is φ = 98422342895472.

The previous prime is 98422342895413. The next prime is 98422342895531. The reversal of 98422342895473 is 37459824322489.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64475953614864 + 33946389280609 = 8029692^2 + 5826353^2 .

It is a cyclic number.

It is not a de Polignac number, because 98422342895473 - 217 = 98422342764401 is a prime.

It is not a weakly prime, because it can be changed into another prime (98422342895413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49211171447736 + 49211171447737.

It is an arithmetic number, because the mean of its divisors is an integer number (49211171447737).

Almost surely, 298422342895473 is an apocalyptic number.

It is an amenable number.

98422342895473 is a deficient number, since it is larger than the sum of its proper divisors (1).

98422342895473 is an equidigital number, since it uses as much as digits as its factorization.

98422342895473 is an evil number, because the sum of its binary digits is even.

The product of its digits is 836075520, while the sum is 70.

The spelling of 98422342895473 in words is "ninety-eight trillion, four hundred twenty-two billion, three hundred forty-two million, eight hundred ninety-five thousand, four hundred seventy-three".