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990000618953 is a prime number
BaseRepresentation
bin11100110100000001010…
…00101001110111001001
310111122100211211020101212
432122000220221313021
5112210010124301303
62034444445022505
7131345065262423
oct16320050516711
93448324736355
10990000618953
113519475a3a15
1213ba51254a35
1372483767018
1435cb8405813
151ab4397bad8
hexe680a29dc9

990000618953 has 2 divisors, whose sum is σ = 990000618954. Its totient is φ = 990000618952.

The previous prime is 990000618911. The next prime is 990000618961. The reversal of 990000618953 is 359816000099.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 886710372409 + 103290246544 = 941653^2 + 321388^2 .

It is an emirp because it is prime and its reverse (359816000099) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 990000618953 - 222 = 989996424649 is a prime.

It is not a weakly prime, because it can be changed into another prime (990000618553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495000309476 + 495000309477.

It is an arithmetic number, because the mean of its divisors is an integer number (495000309477).

Almost surely, 2990000618953 is an apocalyptic number.

It is an amenable number.

990000618953 is a deficient number, since it is larger than the sum of its proper divisors (1).

990000618953 is an equidigital number, since it uses as much as digits as its factorization.

990000618953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 524880, while the sum is 50.

The spelling of 990000618953 in words is "nine hundred ninety billion, six hundred eighteen thousand, nine hundred fifty-three".