Base | Representation |
---|---|
bin | 11100110100000001010… |
… | …00101001110111001001 |
3 | 10111122100211211020101212 |
4 | 32122000220221313021 |
5 | 112210010124301303 |
6 | 2034444445022505 |
7 | 131345065262423 |
oct | 16320050516711 |
9 | 3448324736355 |
10 | 990000618953 |
11 | 3519475a3a15 |
12 | 13ba51254a35 |
13 | 72483767018 |
14 | 35cb8405813 |
15 | 1ab4397bad8 |
hex | e680a29dc9 |
990000618953 has 2 divisors, whose sum is σ = 990000618954. Its totient is φ = 990000618952.
The previous prime is 990000618911. The next prime is 990000618961. The reversal of 990000618953 is 359816000099.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 886710372409 + 103290246544 = 941653^2 + 321388^2 .
It is an emirp because it is prime and its reverse (359816000099) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 990000618953 - 222 = 989996424649 is a prime.
It is not a weakly prime, because it can be changed into another prime (990000618553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495000309476 + 495000309477.
It is an arithmetic number, because the mean of its divisors is an integer number (495000309477).
Almost surely, 2990000618953 is an apocalyptic number.
It is an amenable number.
990000618953 is a deficient number, since it is larger than the sum of its proper divisors (1).
990000618953 is an equidigital number, since it uses as much as digits as its factorization.
990000618953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 524880, while the sum is 50.
The spelling of 990000618953 in words is "nine hundred ninety billion, six hundred eighteen thousand, nine hundred fifty-three".
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