Base | Representation |
---|---|
bin | 11100110100011001010… |
… | …11100011001001000011 |
3 | 10111122212221002020120221 |
4 | 32122030223203021003 |
5 | 112210413343020301 |
6 | 2034520504243511 |
7 | 131353101054112 |
oct | 16321453431103 |
9 | 3448787066527 |
10 | 990202704451 |
11 | 351a40680824 |
12 | 13baa8a70597 |
13 | 724b65a163c |
14 | 35cd71abc79 |
15 | 1ab56598da1 |
hex | e68cae3243 |
990202704451 has 2 divisors, whose sum is σ = 990202704452. Its totient is φ = 990202704450.
The previous prime is 990202704437. The next prime is 990202704511. The reversal of 990202704451 is 154407202099.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 990202704451 - 223 = 990194315843 is a prime.
It is a super-2 number, since 2×9902027044512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 990202704398 and 990202704407.
It is not a weakly prime, because it can be changed into another prime (990202704151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495101352225 + 495101352226.
It is an arithmetic number, because the mean of its divisors is an integer number (495101352226).
Almost surely, 2990202704451 is an apocalyptic number.
990202704451 is a deficient number, since it is larger than the sum of its proper divisors (1).
990202704451 is an equidigital number, since it uses as much as digits as its factorization.
990202704451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 43.
The spelling of 990202704451 in words is "nine hundred ninety billion, two hundred two million, seven hundred four thousand, four hundred fifty-one".
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