Base | Representation |
---|---|
bin | 10110100000111101011011… |
… | …010000010101011010101011 |
3 | 110222121102002120120102101212 |
4 | 112200331123100111122223 |
5 | 100434334030004033323 |
6 | 550334025115503335 |
7 | 26600050343355203 |
oct | 2640753320253253 |
9 | 428542076512355 |
10 | 99022002017963 |
11 | 29607aa4706002 |
12 | b133164157b4b |
13 | 4333972257a5b |
14 | 1a64994913403 |
15 | b6abc9934b78 |
hex | 5a0f5b4156ab |
99022002017963 has 2 divisors, whose sum is σ = 99022002017964. Its totient is φ = 99022002017962.
The previous prime is 99022002017831. The next prime is 99022002017977. The reversal of 99022002017963 is 36971020022099.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-99022002017963 is a prime.
It is not a weakly prime, because it can be changed into another prime (99022002017063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49511001008981 + 49511001008982.
It is an arithmetic number, because the mean of its divisors is an integer number (49511001008982).
Almost surely, 299022002017963 is an apocalyptic number.
99022002017963 is a deficient number, since it is larger than the sum of its proper divisors (1).
99022002017963 is an equidigital number, since it uses as much as digits as its factorization.
99022002017963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 734832, while the sum is 50.
The spelling of 99022002017963 in words is "ninety-nine trillion, twenty-two billion, two million, seventeen thousand, nine hundred sixty-three".
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