Base | Representation |
---|---|
bin | 1110000100111001110101110… |
… | …0011110110011110111010011 |
3 | 11210220021001102010111020002201 |
4 | 3201032131130132303313103 |
5 | 2014313214401412240103 |
6 | 13430422143554224031 |
7 | 415434114232164613 |
oct | 34116353436636723 |
9 | 4726231363436081 |
10 | 990554154024403 |
11 | 267691726287091 |
12 | 93120045b85017 |
13 | 33693b185b8c47 |
14 | 13687110ca6a43 |
15 | 797b8c03cd51d |
hex | 384e75c7b3dd3 |
990554154024403 has 2 divisors, whose sum is σ = 990554154024404. Its totient is φ = 990554154024402.
The previous prime is 990554154024373. The next prime is 990554154024427. The reversal of 990554154024403 is 304420451455099.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 990554154024403 - 25 = 990554154024371 is a prime.
It is not a weakly prime, because it can be changed into another prime (990554154024493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495277077012201 + 495277077012202.
It is an arithmetic number, because the mean of its divisors is an integer number (495277077012202).
Almost surely, 2990554154024403 is an apocalyptic number.
990554154024403 is a deficient number, since it is larger than the sum of its proper divisors (1).
990554154024403 is an equidigital number, since it uses as much as digits as its factorization.
990554154024403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552000, while the sum is 55.
The spelling of 990554154024403 in words is "nine hundred ninety trillion, five hundred fifty-four billion, one hundred fifty-four million, twenty-four thousand, four hundred three".
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