Search a number
-
+
99090000008843 is a prime number
BaseRepresentation
bin10110100001111100110000…
…010000000101011010001011
3110222211220121110210021001112
4112201330300100011122023
5100441442310000240333
6550425152332440535
726605005400634444
oct2641746020053213
9428756543707045
1099090000008843
1129633918808a88
12b14438061914b
13433a1ba9a370c
141a67da56aa2cb
15b6c8593d7948
hex5a1f3040568b

99090000008843 has 2 divisors, whose sum is σ = 99090000008844. Its totient is φ = 99090000008842.

The previous prime is 99090000008801. The next prime is 99090000008849. The reversal of 99090000008843 is 34880000009099.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 99090000008843 - 222 = 99089995814539 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 99090000008791 and 99090000008800.

It is not a weakly prime, because it can be changed into another prime (99090000008849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49545000004421 + 49545000004422.

It is an arithmetic number, because the mean of its divisors is an integer number (49545000004422).

Almost surely, 299090000008843 is an apocalyptic number.

99090000008843 is a deficient number, since it is larger than the sum of its proper divisors (1).

99090000008843 is an equidigital number, since it uses as much as digits as its factorization.

99090000008843 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 559872, while the sum is 50.

The spelling of 99090000008843 in words is "ninety-nine trillion, ninety billion, eight thousand, eight hundred forty-three".