Base | Representation |
---|---|
bin | 10110100001111100110000… |
… | …010000000101011010001011 |
3 | 110222211220121110210021001112 |
4 | 112201330300100011122023 |
5 | 100441442310000240333 |
6 | 550425152332440535 |
7 | 26605005400634444 |
oct | 2641746020053213 |
9 | 428756543707045 |
10 | 99090000008843 |
11 | 29633918808a88 |
12 | b14438061914b |
13 | 433a1ba9a370c |
14 | 1a67da56aa2cb |
15 | b6c8593d7948 |
hex | 5a1f3040568b |
99090000008843 has 2 divisors, whose sum is σ = 99090000008844. Its totient is φ = 99090000008842.
The previous prime is 99090000008801. The next prime is 99090000008849. The reversal of 99090000008843 is 34880000009099.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 99090000008843 - 222 = 99089995814539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 99090000008791 and 99090000008800.
It is not a weakly prime, because it can be changed into another prime (99090000008849) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49545000004421 + 49545000004422.
It is an arithmetic number, because the mean of its divisors is an integer number (49545000004422).
Almost surely, 299090000008843 is an apocalyptic number.
99090000008843 is a deficient number, since it is larger than the sum of its proper divisors (1).
99090000008843 is an equidigital number, since it uses as much as digits as its factorization.
99090000008843 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 50.
The spelling of 99090000008843 in words is "ninety-nine trillion, ninety billion, eight thousand, eight hundred forty-three".
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