Search a number
-
+
991120201001201 is a prime number
BaseRepresentation
bin1110000101011010110010011…
…1100000101010100011110001
311210222021011110220201222211002
43201112230213200222203301
52014402003132424014301
613431534200141331345
7415523033345124035
oct34126544740524361
94728234426658732
10991120201001201
1126788a798018827
12931b1899b66b55
1333705306bc9c7b
14136a668bada1c5
15798b49e57b16b
hex3856b2782a8f1

991120201001201 has 2 divisors, whose sum is σ = 991120201001202. Its totient is φ = 991120201001200.

The previous prime is 991120201001197. The next prime is 991120201001209. The reversal of 991120201001201 is 102100102021199.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 979614944037601 + 11505256963600 = 31298801^2 + 3391940^2 .

It is an emirp because it is prime and its reverse (102100102021199) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 991120201001201 - 22 = 991120201001197 is a prime.

It is a super-2 number, since 2×9911202010012012 (a number of 31 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (991120201001209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495560100500600 + 495560100500601.

It is an arithmetic number, because the mean of its divisors is an integer number (495560100500601).

Almost surely, 2991120201001201 is an apocalyptic number.

It is an amenable number.

991120201001201 is a deficient number, since it is larger than the sum of its proper divisors (1).

991120201001201 is an equidigital number, since it uses as much as digits as its factorization.

991120201001201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 29.

The spelling of 991120201001201 in words is "nine hundred ninety-one trillion, one hundred twenty billion, two hundred one million, one thousand, two hundred one".