Base | Representation |
---|---|
bin | 10010011101101110… |
… | …01100001101000011 |
3 | 221120212002212022221 |
4 | 21032313030031003 |
5 | 130300213302342 |
6 | 4315354311511 |
7 | 500440216351 |
oct | 111667141503 |
9 | 27525085287 |
10 | 9913025347 |
11 | 422770a735 |
12 | 1b07a28597 |
13 | c1c987594 |
14 | 6a07a27d1 |
15 | 3d042ca67 |
hex | 24edcc343 |
9913025347 has 2 divisors, whose sum is σ = 9913025348. Its totient is φ = 9913025346.
The previous prime is 9913025303. The next prime is 9913025357. The reversal of 9913025347 is 7435203199.
9913025347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (7435203199) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 9913025347 - 27 = 9913025219 is a prime.
It is a super-3 number, since 3×99130253473 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (9913025357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4956512673 + 4956512674.
It is an arithmetic number, because the mean of its divisors is an integer number (4956512674).
Almost surely, 29913025347 is an apocalyptic number.
9913025347 is a deficient number, since it is larger than the sum of its proper divisors (1).
9913025347 is an equidigital number, since it uses as much as digits as its factorization.
9913025347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 204120, while the sum is 43.
The square root of 9913025347 is about 99564.1770266796. The cubic root of 9913025347 is about 2148.1704534648.
The spelling of 9913025347 in words is "nine billion, nine hundred thirteen million, twenty-five thousand, three hundred forty-seven".
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