9913403 has 2 divisors, whose sum is σ = 9913404. Its totient is φ = 9913402.

The previous prime is 9913367. The next prime is 9913411. The reversal of 9913403 is 3043199.

9913403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 9913403 - 2⁸ = 9913147 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (9913433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4956701 + 4956702.

It is an arithmetic number, because the mean of its divisors is an integer number (4956702).

Almost surely, 2^9913403 is an apocalyptic number.

9913403 is a deficient number, since it is larger than the sum of its proper divisors (1).

9913403 is an equidigital number, since it uses as much as digits as its factorization.

9913403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 29.

The square root of 9913403 is about 3148.5557006348. Note that the first 3 decimals coincide. The cubic root of 9913403 is about 214.8197732480.

The spelling of 9913403 in words is "nine million, nine hundred thirteen thousand, four hundred three".