9913404811 has 2 divisors, whose sum is σ = 9913404812. Its totient is φ = 9913404810.

The previous prime is 9913404799. The next prime is 9913404841. The reversal of 9913404811 is 1184043199.

9913404811 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (1184043199) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9913404811 - 2²³ = 9905016203 is a prime.

It is not a weakly prime, because it can be changed into another prime (9913404841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4956702405 + 4956702406.

It is an arithmetic number, because the mean of its divisors is an integer number (4956702406).

Almost surely, 2^9913404811 is an apocalyptic number.

9913404811 is a deficient number, since it is larger than the sum of its proper divisors (1).

9913404811 is an equidigital number, since it uses as much as digits as its factorization.

9913404811 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 40.

The square root of 9913404811 is about 99566.0826335957. The cubic root of 9913404811 is about 2148.1978632925.

The spelling of 9913404811 in words is "nine billion, nine hundred thirteen million, four hundred four thousand, eight hundred eleven".