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99149131 is a prime number
BaseRepresentation
bin1011110100011…
…10010101001011
320220120022001001
411322032111023
5200340233011
613501035431
72312516344
oct572162513
9226508031
1099149131
1150a70234
1229255b77
1317706433
14d24d0cb
158a877c1
hex5e8e54b

99149131 has 2 divisors, whose sum is σ = 99149132. Its totient is φ = 99149130.

The previous prime is 99149123. The next prime is 99149137. The reversal of 99149131 is 13194199.

It is a strong prime.

It is an emirp because it is prime and its reverse (13194199) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99149131 - 23 = 99149123 is a prime.

It is a super-2 number, since 2×991491312 = 19661100356110322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (99149137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49574565 + 49574566.

It is an arithmetic number, because the mean of its divisors is an integer number (49574566).

Almost surely, 299149131 is an apocalyptic number.

99149131 is a deficient number, since it is larger than the sum of its proper divisors (1).

99149131 is an equidigital number, since it uses as much as digits as its factorization.

99149131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8748, while the sum is 37.

The square root of 99149131 is about 9957.3656656768. The cubic root of 99149131 is about 462.8386704738.

The spelling of 99149131 in words is "ninety-nine million, one hundred forty-nine thousand, one hundred thirty-one".