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9921364003 is a prime number
BaseRepresentation
bin10010011110101110…
…00000000000100011
3221121102210111211001
421033113000000203
5130304332122003
64320253132431
7500601126325
oct111727000043
927542714731
109921364003
114231395691
121b0a78a117
13c21616bb5
146a1933615
153d102861d
hex24f5c0023

9921364003 has 2 divisors, whose sum is σ = 9921364004. Its totient is φ = 9921364002.

The previous prime is 9921363943. The next prime is 9921364043. The reversal of 9921364003 is 3004631299.

It is a strong prime.

It is an emirp because it is prime and its reverse (3004631299) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-9921364003 is a prime.

It is not a weakly prime, because it can be changed into another prime (9921364043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4960682001 + 4960682002.

It is an arithmetic number, because the mean of its divisors is an integer number (4960682002).

Almost surely, 29921364003 is an apocalyptic number.

9921364003 is a deficient number, since it is larger than the sum of its proper divisors (1).

9921364003 is an equidigital number, since it uses as much as digits as its factorization.

9921364003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34992, while the sum is 37.

The square root of 9921364003 is about 99606.0440083833. The cubic root of 9921364003 is about 2148.7726185793.

It can be divided in two parts, 99213 and 64003, that added together give a square (163216 = 4042).

The spelling of 9921364003 in words is "nine billion, nine hundred twenty-one million, three hundred sixty-four thousand, three".