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99330340969 is a prime number
BaseRepresentation
bin101110010000010001…
…1001011100001101001
3100111101111120010202101
41130200203023201221
53111412031402334
6113344241533401
710114332652546
oct1344043134151
9314344503671
1099330340969
113914242a392
1217301644261
13949cb645b2
144b44143bcd
1528b555c214
hex17208cb869

99330340969 has 2 divisors, whose sum is σ = 99330340970. Its totient is φ = 99330340968.

The previous prime is 99330340951. The next prime is 99330340973. The reversal of 99330340969 is 96904303399.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99327716569 + 2624400 = 315163^2 + 1620^2 .

It is a cyclic number.

It is not a de Polignac number, because 99330340969 - 215 = 99330308201 is a prime.

It is a super-3 number, since 3×993303409693 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (99330340979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49665170484 + 49665170485.

It is an arithmetic number, because the mean of its divisors is an integer number (49665170485).

Almost surely, 299330340969 is an apocalyptic number.

It is an amenable number.

99330340969 is a deficient number, since it is larger than the sum of its proper divisors (1).

99330340969 is an equidigital number, since it uses as much as digits as its factorization.

99330340969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4251528, while the sum is 55.

The spelling of 99330340969 in words is "ninety-nine billion, three hundred thirty million, three hundred forty thousand, nine hundred sixty-nine".