Base | Representation |
---|---|
bin | 1110000111011100110111010… |
… | …1111100110100101100000011 |
3 | 11211021011210121221011021111101 |
4 | 3201313031311330310230003 |
5 | 2020200111313344440431 |
6 | 13440404535144355231 |
7 | 416143344310161331 |
oct | 34167156574645403 |
9 | 4737153557137441 |
10 | 993354899999491 |
11 | 2685714a13827a7 |
12 | 934b2a02175b17 |
13 | 33837c71515453 |
14 | 137428c2bc2b51 |
15 | 79c9691e02961 |
hex | 3877375f34b03 |
993354899999491 has 2 divisors, whose sum is σ = 993354899999492. Its totient is φ = 993354899999490.
The previous prime is 993354899999461. The next prime is 993354899999503. The reversal of 993354899999491 is 194999998453399.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 993354899999491 - 241 = 991155876743939 is a prime.
It is not a weakly prime, because it can be changed into another prime (993354899999461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496677449999745 + 496677449999746.
It is an arithmetic number, because the mean of its divisors is an integer number (496677449999746).
Almost surely, 2993354899999491 is an apocalyptic number.
993354899999491 is a deficient number, since it is larger than the sum of its proper divisors (1).
993354899999491 is an equidigital number, since it uses as much as digits as its factorization.
993354899999491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 247949112960, while the sum is 100.
The spelling of 993354899999491 in words is "nine hundred ninety-three trillion, three hundred fifty-four billion, eight hundred ninety-nine million, nine hundred ninety-nine thousand, four hundred ninety-one".
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