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99341420513 is a prime number
BaseRepresentation
bin101110010000100110…
…1011100011111100001
3100111102021102001000212
41130201031130133201
53111422400424023
6113345315223505
710114526066456
oct1344115343741
9314367361025
1099341420513
1139148707635
12173052a7b95
1394a224363a
144b457c982d
1528b64e9e78
hex172135c7e1

99341420513 has 2 divisors, whose sum is σ = 99341420514. Its totient is φ = 99341420512.

The previous prime is 99341420501. The next prime is 99341420539. The reversal of 99341420513 is 31502414399.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68614135249 + 30727285264 = 261943^2 + 175292^2 .

It is an emirp because it is prime and its reverse (31502414399) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99341420513 - 212 = 99341416417 is a prime.

It is not a weakly prime, because it can be changed into another prime (99341420573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49670710256 + 49670710257.

It is an arithmetic number, because the mean of its divisors is an integer number (49670710257).

Almost surely, 299341420513 is an apocalyptic number.

It is an amenable number.

99341420513 is a deficient number, since it is larger than the sum of its proper divisors (1).

99341420513 is an equidigital number, since it uses as much as digits as its factorization.

99341420513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 116640, while the sum is 41.

The spelling of 99341420513 in words is "ninety-nine billion, three hundred forty-one million, four hundred twenty thousand, five hundred thirteen".