9934334000323 has 2 divisors, whose sum is σ = 9934334000324. Its totient is φ = 9934334000322.

The previous prime is 9934334000257. The next prime is 9934334000333. The reversal of 9934334000323 is 3230004334399.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-9934334000323 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 9934334000323.

It is not a weakly prime, because it can be changed into another prime (9934334000333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4967167000161 + 4967167000162.

It is an arithmetic number, because the mean of its divisors is an integer number (4967167000162).

Almost surely, 2^{9934334000323} is an apocalyptic number.

9934334000323 is a deficient number, since it is larger than the sum of its proper divisors (1).

9934334000323 is an equidigital number, since it uses as much as digits as its factorization.

9934334000323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 629856, while the sum is 43.

The spelling of 9934334000323 in words is "nine trillion, nine hundred thirty-four billion, three hundred thirty-four million, three hundred twenty-three", and thus it is an aban number.