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994000000055 = 5395635024897
BaseRepresentation
bin11100111011011110000…
…01000101010000110111
310112000200120100211212212
432131233001011100313
5112241203000000210
62040345353404035
7131546150410556
oct16355701052067
93460616324785
10994000000055
1135360a0a5157
1214078870961b
13729701ccb0a
1436177637d9d
151acc9b2d805
hexe76f045437

994000000055 has 8 divisors (see below), whose sum is σ = 1192830386832. Its totient is φ = 795179742208.

The previous prime is 994000000051. The next prime is 994000000087. The reversal of 994000000055 is 550000000499.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 994000000055 - 22 = 994000000051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 993999999958 and 994000000030.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (994000000051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2314634 + ... + 2710263.

It is an arithmetic number, because the mean of its divisors is an integer number (149103798354).

Almost surely, 2994000000055 is an apocalyptic number.

994000000055 is a deficient number, since it is larger than the sum of its proper divisors (198830386777).

994000000055 is a wasteful number, since it uses less digits than its factorization.

994000000055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5064465.

The product of its (nonzero) digits is 8100, while the sum is 32.

The spelling of 994000000055 in words is "nine hundred ninety-four billion, fifty-five", and thus it is an aban number.

Divisors: 1 5 39563 197815 5024897 25124485 198800000011 994000000055