Base | Representation |
---|---|
bin | 11100111011011110000… |
… | …01000101010000110111 |
3 | 10112000200120100211212212 |
4 | 32131233001011100313 |
5 | 112241203000000210 |
6 | 2040345353404035 |
7 | 131546150410556 |
oct | 16355701052067 |
9 | 3460616324785 |
10 | 994000000055 |
11 | 35360a0a5157 |
12 | 14078870961b |
13 | 729701ccb0a |
14 | 36177637d9d |
15 | 1acc9b2d805 |
hex | e76f045437 |
994000000055 has 8 divisors (see below), whose sum is σ = 1192830386832. Its totient is φ = 795179742208.
The previous prime is 994000000051. The next prime is 994000000087. The reversal of 994000000055 is 550000000499.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 994000000055 - 22 = 994000000051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 993999999958 and 994000000030.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (994000000051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2314634 + ... + 2710263.
It is an arithmetic number, because the mean of its divisors is an integer number (149103798354).
Almost surely, 2994000000055 is an apocalyptic number.
994000000055 is a deficient number, since it is larger than the sum of its proper divisors (198830386777).
994000000055 is a wasteful number, since it uses less digits than its factorization.
994000000055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5064465.
The product of its (nonzero) digits is 8100, while the sum is 32.
The spelling of 994000000055 in words is "nine hundred ninety-four billion, fifty-five", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •