9940115803 has 2 divisors, whose sum is σ = 9940115804. Its totient is φ = 9940115802.

The previous prime is 9940115789. The next prime is 9940115813. The reversal of 9940115803 is 3085110499.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 9940115803 - 2¹⁷ = 9939984731 is a prime.

It is not a weakly prime, because it can be changed into another prime (9940115813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4970057901 + 4970057902.

It is an arithmetic number, because the mean of its divisors is an integer number (4970057902).

Almost surely, 2^9940115803 is an apocalyptic number.

9940115803 is a deficient number, since it is larger than the sum of its proper divisors (1).

9940115803 is an equidigital number, since it uses as much as digits as its factorization.

9940115803 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 40.

The square root of 9940115803 is about 99700.1294031257. The cubic root of 9940115803 is about 2150.1255238053.

The spelling of 9940115803 in words is "nine billion, nine hundred forty million, one hundred fifteen thousand, eight hundred three".