Base | Representation |
---|---|
bin | 11100111100000101011… |
… | …00000011101100111001 |
3 | 10112001112120101020220112 |
4 | 32132002230003230321 |
5 | 112242341442023303 |
6 | 2040442223234105 |
7 | 131560265553605 |
oct | 16360254035471 |
9 | 3461476336815 |
10 | 994330032953 |
11 | 353769421814 |
12 | 14085b148935 |
13 | 729c36b485a |
14 | 361a93c8505 |
15 | 1ace8ac10d8 |
hex | e782b03b39 |
994330032953 has 2 divisors, whose sum is σ = 994330032954. Its totient is φ = 994330032952.
The previous prime is 994330032931. The next prime is 994330032959. The reversal of 994330032953 is 359230033499.
994330032953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 956223869689 + 38106163264 = 977867^2 + 195208^2 .
It is a cyclic number.
It is not a de Polignac number, because 994330032953 - 238 = 719452126009 is a prime.
It is not a weakly prime, because it can be changed into another prime (994330032959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497165016476 + 497165016477.
It is an arithmetic number, because the mean of its divisors is an integer number (497165016477).
Almost surely, 2994330032953 is an apocalyptic number.
It is an amenable number.
994330032953 is a deficient number, since it is larger than the sum of its proper divisors (1).
994330032953 is an equidigital number, since it uses as much as digits as its factorization.
994330032953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2361960, while the sum is 50.
The spelling of 994330032953 in words is "nine hundred ninety-four billion, three hundred thirty million, thirty-two thousand, nine hundred fifty-three".
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