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994330032953 is a prime number
BaseRepresentation
bin11100111100000101011…
…00000011101100111001
310112001112120101020220112
432132002230003230321
5112242341442023303
62040442223234105
7131560265553605
oct16360254035471
93461476336815
10994330032953
11353769421814
1214085b148935
13729c36b485a
14361a93c8505
151ace8ac10d8
hexe782b03b39

994330032953 has 2 divisors, whose sum is σ = 994330032954. Its totient is φ = 994330032952.

The previous prime is 994330032931. The next prime is 994330032959. The reversal of 994330032953 is 359230033499.

994330032953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 956223869689 + 38106163264 = 977867^2 + 195208^2 .

It is a cyclic number.

It is not a de Polignac number, because 994330032953 - 238 = 719452126009 is a prime.

It is not a weakly prime, because it can be changed into another prime (994330032959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497165016476 + 497165016477.

It is an arithmetic number, because the mean of its divisors is an integer number (497165016477).

Almost surely, 2994330032953 is an apocalyptic number.

It is an amenable number.

994330032953 is a deficient number, since it is larger than the sum of its proper divisors (1).

994330032953 is an equidigital number, since it uses as much as digits as its factorization.

994330032953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2361960, while the sum is 50.

The spelling of 994330032953 in words is "nine hundred ninety-four billion, three hundred thirty million, thirty-two thousand, nine hundred fifty-three".