Base | Representation |
---|---|
bin | 11100111100000101011… |
… | …00000011111000011011 |
3 | 10112001112120101021220212 |
4 | 32132002230003320123 |
5 | 112242341442034231 |
6 | 2040442223241335 |
7 | 131560265556011 |
oct | 16360254037033 |
9 | 3461476337825 |
10 | 994330033691 |
11 | 353769422325 |
12 | 14085b14924b |
13 | 729c36b4ca7 |
14 | 361a93c88b1 |
15 | 1ace8ac142b |
hex | e782b03e1b |
994330033691 has 2 divisors, whose sum is σ = 994330033692. Its totient is φ = 994330033690.
The previous prime is 994330033679. The next prime is 994330033699. The reversal of 994330033691 is 196330033499.
994330033691 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-994330033691 is a prime.
It is not a weakly prime, because it can be changed into another prime (994330033699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497165016845 + 497165016846.
It is an arithmetic number, because the mean of its divisors is an integer number (497165016846).
Almost surely, 2994330033691 is an apocalyptic number.
994330033691 is a deficient number, since it is larger than the sum of its proper divisors (1).
994330033691 is an equidigital number, since it uses as much as digits as its factorization.
994330033691 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1417176, while the sum is 50.
The spelling of 994330033691 in words is "nine hundred ninety-four billion, three hundred thirty million, thirty-three thousand, six hundred ninety-one".
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