9944001323 has 2 divisors, whose sum is σ = 9944001324. Its totient is φ = 9944001322.

The previous prime is 9944001281. The next prime is 9944001337. The reversal of 9944001323 is 3231004499.

9944001323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (3231004499) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9944001323 - 2⁶ = 9944001259 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (9944001623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4972000661 + 4972000662.

It is an arithmetic number, because the mean of its divisors is an integer number (4972000662).

Almost surely, 2^9944001323 is an apocalyptic number.

9944001323 is a deficient number, since it is larger than the sum of its proper divisors (1).

9944001323 is an equidigital number, since it uses as much as digits as its factorization.

9944001323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 35.

The square root of 9944001323 is about 99719.6135321432. The cubic root of 9944001323 is about 2150.4056435268.

The spelling of 9944001323 in words is "nine billion, nine hundred forty-four million, one thousand, three hundred twenty-three".