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9945973153 is a prime number
BaseRepresentation
bin10010100001101001…
…11000000110100001
3221200011002210020001
421100310320012201
5130332132120103
64322532420001
7501320243164
oct112064700641
927604083201
109945973153
114244273926
121b16a77601
13c2675221c
146a4cdbadb
153d328a01d
hex250d381a1

9945973153 has 2 divisors, whose sum is σ = 9945973154. Its totient is φ = 9945973152.

The previous prime is 9945973127. The next prime is 9945973171. The reversal of 9945973153 is 3513795499.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8996901904 + 949071249 = 94852^2 + 30807^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-9945973153 is a prime.

It is a super-2 number, since 2×99459731532 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 9945973094 and 9945973103.

It is not a weakly prime, because it can be changed into another prime (9945973253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4972986576 + 4972986577.

It is an arithmetic number, because the mean of its divisors is an integer number (4972986577).

Almost surely, 29945973153 is an apocalyptic number.

It is an amenable number.

9945973153 is a deficient number, since it is larger than the sum of its proper divisors (1).

9945973153 is an equidigital number, since it uses as much as digits as its factorization.

9945973153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4592700, while the sum is 55.

The square root of 9945973153 is about 99729.4999135161. The cubic root of 9945973153 is about 2150.5477712271.

The spelling of 9945973153 in words is "nine billion, nine hundred forty-five million, nine hundred seventy-three thousand, one hundred fifty-three".