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99464830403 is a prime number
BaseRepresentation
bin101110010100010010…
…0001101110111000011
3100111201212121220120112
41130220210031313003
53112200444033103
6113405444301535
710120555052201
oct1345044156703
9314655556515
1099464830403
1139201338284
121733a6a18ab
1394c1992643
144b57d52071
1528c2275cd8
hex172890ddc3

99464830403 has 2 divisors, whose sum is σ = 99464830404. Its totient is φ = 99464830402.

The previous prime is 99464830363. The next prime is 99464830417. The reversal of 99464830403 is 30403846499.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 99464830403 - 214 = 99464814019 is a prime.

It is not a weakly prime, because it can be changed into another prime (99464830453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49732415201 + 49732415202.

It is an arithmetic number, because the mean of its divisors is an integer number (49732415202).

Almost surely, 299464830403 is an apocalyptic number.

99464830403 is a deficient number, since it is larger than the sum of its proper divisors (1).

99464830403 is an equidigital number, since it uses as much as digits as its factorization.

99464830403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2239488, while the sum is 50.

The spelling of 99464830403 in words is "ninety-nine billion, four hundred sixty-four million, eight hundred thirty thousand, four hundred three".