Base | Representation |
---|---|
bin | 11100111100101011111… |
… | …00000101000110100001 |
3 | 10112002101002002200112121 |
4 | 32132111330011012201 |
5 | 112244022132000342 |
6 | 2040534241424241 |
7 | 131601300001021 |
oct | 16362574050641 |
9 | 3462332080477 |
10 | 994653000097 |
11 | 353914762809 |
12 | 14092b33b081 |
13 | 72a45594483 |
14 | 361da259a81 |
15 | 1ad1711a067 |
hex | e795f051a1 |
994653000097 has 2 divisors, whose sum is σ = 994653000098. Its totient is φ = 994653000096.
The previous prime is 994653000091. The next prime is 994653000139. The reversal of 994653000097 is 790000356499.
994653000097 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 814477370256 + 180175629841 = 902484^2 + 424471^2 .
It is a cyclic number.
It is not a de Polignac number, because 994653000097 - 219 = 994652475809 is a prime.
It is not a weakly prime, because it can be changed into another prime (994653000091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497326500048 + 497326500049.
It is an arithmetic number, because the mean of its divisors is an integer number (497326500049).
Almost surely, 2994653000097 is an apocalyptic number.
It is an amenable number.
994653000097 is a deficient number, since it is larger than the sum of its proper divisors (1).
994653000097 is an equidigital number, since it uses as much as digits as its factorization.
994653000097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1837080, while the sum is 52.
The spelling of 994653000097 in words is "nine hundred ninety-four billion, six hundred fifty-three million, ninety-seven", and thus it is an aban number.
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