Base | Representation |
---|---|
bin | 10110100111011111000101… |
… | …001100101001001101011101 |
3 | 111001012021122002220211220110 |
4 | 112213133011030221031131 |
5 | 101014210443221043031 |
6 | 551320032513440233 |
7 | 26644334425534413 |
oct | 2647370514511535 |
9 | 431167562824813 |
10 | 99470456034141 |
11 | 29770202272975 |
12 | b1a605a570079 |
13 | 436704026348a |
14 | 1a7c577d732b3 |
15 | b776c50e3c46 |
hex | 5a77c532935d |
99470456034141 has 32 divisors (see below), whose sum is σ = 140069835988992. Its totient is φ = 62662292285120.
The previous prime is 99470456034097. The next prime is 99470456034163. The reversal of 99470456034141 is 14143065407499.
It is a cyclic number.
It is not a de Polignac number, because 99470456034141 - 217 = 99470455903069 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (99470456034041) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 92373811 + ... + 93444431.
It is an arithmetic number, because the mean of its divisors is an integer number (4377182374656).
Almost surely, 299470456034141 is an apocalyptic number.
It is an amenable number.
99470456034141 is a deficient number, since it is larger than the sum of its proper divisors (40599379954851).
99470456034141 is a wasteful number, since it uses less digits than its factorization.
99470456034141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1086953.
The product of its (nonzero) digits is 13063680, while the sum is 57.
The spelling of 99470456034141 in words is "ninety-nine trillion, four hundred seventy billion, four hundred fifty-six million, thirty-four thousand, one hundred forty-one".
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