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99478310081 is a prime number
BaseRepresentation
bin101110010100101011…
…1101000110011000001
3100111202210222202012212
41130221113220303001
53112212421410311
6113411045231505
710121110453433
oct1345127506301
9314683882185
1099478310081
1139208a04807
1217343102595
1394c4701c97
144b59a60653
1528c3539c8b
hex17295e8cc1

99478310081 has 2 divisors, whose sum is σ = 99478310082. Its totient is φ = 99478310080.

The previous prime is 99478310027. The next prime is 99478310143. The reversal of 99478310081 is 18001387499.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50542233856 + 48936076225 = 224816^2 + 221215^2 .

It is a cyclic number.

It is not a de Polignac number, because 99478310081 - 226 = 99411201217 is a prime.

It is a super-2 number, since 2×994783100812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (99478310011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49739155040 + 49739155041.

It is an arithmetic number, because the mean of its divisors is an integer number (49739155041).

Almost surely, 299478310081 is an apocalyptic number.

It is an amenable number.

99478310081 is a deficient number, since it is larger than the sum of its proper divisors (1).

99478310081 is an equidigital number, since it uses as much as digits as its factorization.

99478310081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 435456, while the sum is 50.

The spelling of 99478310081 in words is "ninety-nine billion, four hundred seventy-eight million, three hundred ten thousand, eighty-one".