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994848409 is a prime number
BaseRepresentation
bin111011010011000…
…010111010011001
32120022222112110101
4323103002322121
54014140122114
6242415015401
733440033452
oct7323027231
92508875411
10994848409
11470625375
1223920a561
1312b1553c9
14961aa129
155c514d74
hex3b4c2e99

994848409 has 2 divisors, whose sum is σ = 994848410. Its totient is φ = 994848408.

The previous prime is 994848401. The next prime is 994848419. The reversal of 994848409 is 904848499.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 738752400 + 256096009 = 27180^2 + 16003^2 .

It is an emirp because it is prime and its reverse (904848499) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 994848409 - 23 = 994848401 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 994848409.

It is not a weakly prime, because it can be changed into another prime (994848401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497424204 + 497424205.

It is an arithmetic number, because the mean of its divisors is an integer number (497424205).

Almost surely, 2994848409 is an apocalyptic number.

It is an amenable number.

994848409 is a deficient number, since it is larger than the sum of its proper divisors (1).

994848409 is an equidigital number, since it uses as much as digits as its factorization.

994848409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2985984, while the sum is 55.

The square root of 994848409 is about 31541.2176207578. The cubic root of 994848409 is about 998.2798457660.

The spelling of 994848409 in words is "nine hundred ninety-four million, eight hundred forty-eight thousand, four hundred nine".