Base | Representation |
---|---|
bin | 1001000011001001010100… |
… | …1100110011111100011011 |
3 | 1022020011210000222020000212 |
4 | 2100302111030303330123 |
5 | 2301003334214434321 |
6 | 33054445510321335 |
7 | 2044560352444121 |
oct | 220622514637433 |
9 | 38204700866025 |
10 | 9949647421211 |
11 | 3196692645343 |
12 | 114838495924b |
13 | 57232b33b8c4 |
14 | 2657cba5d911 |
15 | 123c2e65555b |
hex | 90c95333f1b |
9949647421211 has 2 divisors, whose sum is σ = 9949647421212. Its totient is φ = 9949647421210.
The previous prime is 9949647421171. The next prime is 9949647421279. The reversal of 9949647421211 is 1121247469499.
9949647421211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (1121247469499) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-9949647421211 is a prime.
It is not a weakly prime, because it can be changed into another prime (9949647427211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4974823710605 + 4974823710606.
It is an arithmetic number, because the mean of its divisors is an integer number (4974823710606).
Almost surely, 29949647421211 is an apocalyptic number.
9949647421211 is a deficient number, since it is larger than the sum of its proper divisors (1).
9949647421211 is an equidigital number, since it uses as much as digits as its factorization.
9949647421211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7838208, while the sum is 59.
The spelling of 9949647421211 in words is "nine trillion, nine hundred forty-nine billion, six hundred forty-seven million, four hundred twenty-one thousand, two hundred eleven".
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