Base | Representation |
---|---|
bin | 1001000011011011100011… |
… | …0100011111100000101011 |
3 | 1022020122102000012121222021 |
4 | 2100312320310133200223 |
5 | 2301043344214240011 |
6 | 33101015203205311 |
7 | 2045122531561156 |
oct | 220667064374053 |
9 | 38218360177867 |
10 | 9954539993131 |
11 | 3198773348008 |
12 | 114930b376837 |
13 | 57292ab55986 |
14 | 265b33758c9d |
15 | 123e18e3b471 |
hex | 90db8d1f82b |
9954539993131 has 2 divisors, whose sum is σ = 9954539993132. Its totient is φ = 9954539993130.
The previous prime is 9954539993087. The next prime is 9954539993141. The reversal of 9954539993131 is 1313999354599.
9954539993131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 9954539993131 - 29 = 9954539992619 is a prime.
It is a super-2 number, since 2×99545399931312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (9954539993141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4977269996565 + 4977269996566.
It is an arithmetic number, because the mean of its divisors is an integer number (4977269996566).
Almost surely, 29954539993131 is an apocalyptic number.
9954539993131 is a deficient number, since it is larger than the sum of its proper divisors (1).
9954539993131 is an equidigital number, since it uses as much as digits as its factorization.
9954539993131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 159432300, while the sum is 70.
The spelling of 9954539993131 in words is "nine trillion, nine hundred fifty-four billion, five hundred thirty-nine million, nine hundred ninety-three thousand, one hundred thirty-one".
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